max height obtained = u2sin2θ2g
horizontal range = 2usinθ*ucosθg
equating both, we get
sinθ/2 = 2cosθ
=> tanθ = 4
=> sin2θ = 16/17
=> max height = max range = u21617*2g= 8u2/17g
 Raunaq Saha why is sin2θ = 16/17 ?Upvote·0· Reply ·2013-06-28 19:35:42 Raunaq Saha why is sin2θ = 16/17 ?Upvote·0· Reply ·2013-06-28 19:35:42
 Himanshu Giria 1 + tan2 theta = sec2 theta.      and.               cos theta = 1 / sec theta.      And.              sin2 theta =  1 - cos 2 theta Himanshu Giria 1 + tan2 theta = sec2 theta.      and.               cos theta = 1 / sec theta.      And.              sin2 theta =  1 - cos 2 theta
 
