projectile

A body is projected with a speed u in such a direction that the maximum height obtained is equal to its horizontal range. The horizontal range is
a)8u2/17g
b)5u2/17g
c)6u2/13g
d)u2/2g

3 Answers

106
Asish Mahapatra ·

max height obtained = u2sin2θ2g

horizontal range = 2usinθ*ucosθg

equating both, we get
sinθ/2 = 2cosθ

=> tanθ = 4
=> sin2θ = 16/17
=> max height = max range = u21617*2g= 8u2/17g

481
Anurag Ghosh ·

A. is d answer

1
swastik ·

from which bk r u asking this can u pls tell me

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