cross out 10 digits from the number 1234512345123451234512345 so that remaining number is as large as possible.then what will be the addition of all the digits of the new number?
a.51
b.52
c.48
d.56
show me the process of doin this puzzle
29In this question i am getting the answer 52..
the way i solved this question..since we have to eliminate 10 numbers so let's start eliminating 1234 then 1234 again and then 12..so the number obtained is
553451234512345
the sum of the digits is 52..
49tht ll giv largest no possibly!![1][1][1]
then add the digits!!
49ohh sorry never saw there anre 5 1 s!!
so we delete
1234 1111 22
1hw cant tht be ....5..3 or 53abcd>>
be greater than 55abcd>>(equal no of digits)
49yeah!!
that is even true!!
man confused myself! and the heat is gettng on my nerves!!