11.05*3.763=3.95115
a physical quantity is related to four variables as
Ω =( a^3.b^2 ) / √y . n
the percentage errors in measurement of a,b,y,n are 1%,3%,4% and 2% respectively. if value of Ω is calculated as 3.763 unit from the given values...to what value should you round off the result ??
one who gets this questions' solution is really a genius according to me....
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