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above is a rod having a perpendicular extension MN which has a container permanently fixed to it ..

the container contains water full to its top..

the rod was rotated in such a way that water comes out of the hole of container in a constant rate ..

draw the graph of the tension in the MN with time?

5 Answers

1
Abhisek ·

Is it a Straight Line with negative slope? [7]

71
Vivek @ Born this Way ·

And how do you assert your answer.!?

1
nihal raj ·

in a detailed manner.......

1
nihal raj ·

someone try ....

11
jeetopper jee ·

COMPLETE ANALYSIS OF THE SYSTEM.

if we sit on the rotating rod assumed to be rotating with constant ω
Then the box will experience a force ∫dmω2x where x is its distance from the axis.
The volume dQ is changing at constant rate
∫dQ=-∫kdt
Q=-kt
∫dm=∫ρdQ
m=ρkt
f=ρktω2x

The water comming out will have some velocity v=xω n thus momentum change per second will give the force with which it will come out.

it will also experience a normal force perpendicular to surface.

Now since box is stationary applyΣf=0 n calculat the normal force being experienced by the rod.

THE rod is in circular motion and has ar nat

NOW tension can be calculated
IF say normal force is N the taking torque about joint
NL/2=Icmα

due to this α the ω is not constant n is changing
At any t time ω'=ω+αt
now consider any infinitesimal element dx with mass dm
At instant of t
dm=σdx
∫dT=∫dmω2 x
∫σω2xdx=Mω'2L/2
I think from the above analysis the graph should be parabola.

(although i am not very sure )

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