59there's an easier way...
A=√1+1+√2=2
Ax=1=2cosθx=>cosθx=1/2 =>θx=60°
Ay=1=2cosθy=>cosθy=1/2 =>θy=60°
Az=√2=2cosθz=>cosθz=1/√2 =>θz=45°
the angles which a vector A = i+j+√2k makes with X Y Z axes respectively are
a) 60° 60° 60°
b) 45° 45° 45°
c) 60° 60° 45°
d) 45° 45° 60°
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3 Answers
45C)60°,60° and 45°
angle with x-axis :
cosθ= A.B|A||B|=1√1+1+2=12
θ=60°
angle with y-axis :
cosθ= A.B|A||B|=1√1+1+2=12
θ=60°
angle with z-axis :
cosθ= A.B|A||B|=√2√1+1+2=1√2
θ=45°
Manish Sarkar in the determination of angle with z-axis...why is A.B =root 2???Upvote·0· Reply ·2013-06-22 06:38:10- Raunaq Saha i+j+√2k.k=√2 isn't it ?
- Manish Sarkar ummmm yesss!!!
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