Vectros-2

here, tan^-1(√3/2)=tan^-1(2sinθ/1+2sinθ)
so, 2sinθ=√3 and 1+2sinθ=2
either ways the value of θ equals to 60°

did some mistakes in the previous comment..
here, tan-1(√3/2)=tan-1(2sinθ/1+2cosθ)
so, 2sinθ=√3 and 1+2cosθ=2
either ways the value of θ equals to 60°

apply,angle made with p=(q sin theta)/p+ q cos theta

answer is (D)
√3/2=(2Psinx)/P+2Pcosx