work energy theorem problem

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A body of mass 2 kg is projected at an angle of 60Â° to the horizontal with a speed of 20 m/s. The work done by gravity by the time it makes 30Â° to the horizontal (g=10m/s)?

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rishabh ·2011-09-28 01:29:58

use the fact that horizontal velocity doesnt change to get the vel. @ tht instant now use v² - u² = 2gh to get h and work done = -mgh = -800/3 .

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Basic Integral Calculus Operators Symbols Matrix Cases

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∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

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work energy theorem problem

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