{x}{y}={xy}
=> 0<= {x}{y} < 1
=> 0<= {y} < 1/{x}
am i correct?
{x}{y}={xy} is satisfied for integer pts sky and so graph will be "the origin only at integer pts".
that is the graph will be a pt circle having center at origin for integer pts
x=5.1/2
y=6.1/2
xy=30.1/4
{x}=1/2 , {y}=1/2
{xy}=1/4 ={x}{y}
so...
y only integer points?
in the 2nd post u can divide the {x} term only at pts other than integer points
waah
sir u r really gr8
guys
don't let Nishant Sir hardwork go in vain .
Brilliant question!
I have no idea of what your sir has done..
doesnt seem correct to me...
For instance it does not depict the integer points.. all integer points are satisfied.. [1]