-ve x will not b defined.....
otherwise kuch zyada fark padega kya ? ie frm y = sinx
here the maxima will be attained at (pi/2)2 and the period of the functn will bcum
(2Ï€)2
-ve x will not b defined.....
otherwise kuch zyada fark padega kya ? ie frm y = sinx
here the maxima will be attained at (pi/2)2 and the period of the functn will bcum
(2Ï€)2
lemme chk....
t = √x
y = sint
t is always +ve.....
shud i take sin-1y = √x and then solve????
mere ko galti nahi mil rahi [2]
OHHHHH NO!!!!!!!!!
HOW CUD I MISS DAT!!!!!
K2(2Ï€)2 WILL BE PERIODIC......
that means this oscillatory motion not SHM (LOL [3] [6])
I need a bit more info on this one
and more than that
I preferably need a graph for this one :) ;)