1cos x =1 ka graph.....so (0,nÎ )
another justification is that in (0,Î ) tan x > sin x
so we can have only the points (nÎ ,0) as the graph..
24sinx=tanx
=>sinx(1-1/cosx)=0
=> sinx=0 or cosx=1
=>x=nπ or x=2mπ+0=2mπ
=>x=0,Ï€,2Ï€... or x=0,2Ï€,4Ï€...
1intersection points at 0,pi,2 pi....
24
eureka123
·2009-10-01 10:52:58
basically y=sinx,y=tanx,y=x touch each other ....
24
eureka123
·2009-10-01 10:57:13
[1]
this is a famous ques in limits chap [6]
1
RAY
·2009-10-02 05:42:47
chats the aswner guys???which points???
