5 Answers
eureka123
·2009-10-01 10:40:37
sin2x(1+sin2x)=y
Dom=R
Range::
-1≤sinx≤1 => 0≤sin2x≤1 & 1≤1+sin2x≤2
=> 0≤sin2x(1+sin2x)≤2
f(x)=f(-x)
=> even function
period=2Ï€/2=Ï€
f(x)=sin 2x + sin4x
f'(x)=2sinx.cosx+4sin3xcosx=2sinx.cosx(1+2sin2x)
f'(x)>0 when sinx.cosx>0 =>x ε[0,π/2]
f'(x)<0 when sinx.cosx<0 =>x ε[π/2,π]
f'(x)=0 => sinx=0 or cosx=0
=> x=nπ or x=(2m+1)π/2
=> x=0,Ï€... or x=Ï€/2,3Ï€/2...
easy now..
eureka123
·2009-10-01 10:47:22
no worries.....it happens a lot of times[1][1]
atleast I know I ma rite [1]