Daily Graph 06-02-09

x²+y²=x²-y²+I

2y²=I

y²= I [4]

**************************edit**************************
x²+y²=x²-y²+I

2y²= a ; a belongs to set of integers

y²= b ; b still belongs to the set of integers [4]

hope the confusion is cleared.

i used I bcos it is the symbol commonly used to denote an integer [4]

x values don't matter. y values are sq roots of integers...........like √2, √3, et cetera.
As we go up the y axis, the number of such values between two integers increases............for eg. √2and √3 lie between 1 and 2. √5, √6, √7 and √8 lie between 2 and 3 and sq roots of all integers from 9 to 15 lie b/w 3 and 4.............

HOPE U UNDERSTAND [4]

First I is diff from second I [3][4]
Anyways, both are integers [4]
Btw, why no pink for my graph? [3]

machan let the first I be 1 and then the second I will be 1/2 not an integer da. but i think ur second I shows the no is an integer

OK machans.........no need to get confused.........I'll edit it for you. [4]

That's why the graph will be only for specific values of RHS

And a small clarification: y=0 is included in the graph [4]

what if y =1/√2

2y² = I
but y² is not integer
that is the doubt i have
please clear this ani..

THE TOPOGRAFY OF DA GRAF REMAINS UNCHANGED BUT DA VALUEAS U MUST IDEALLY PLOT WILL CHANG....

THE CREDIT 4 CORE LOGIC GOES 2 U ANI...

JUS A SLIGHT CHANGE(MAYB)

SAMPLE VALUES OF WILL BCUM :

√(1/2) , √(2/2) , √(3/2) ETC......

AND NOT √2and √3, √5, √6, √7 and √8

yeah........tapan got ur point........basic shape is same.........but Rhs changes.......thanx for the correction [4]