25 Answers
sir wat do u think about this 1 ????
done or still plenty to be done????
ooooooooooooooooooooops...
sorry bhaiya......brain not working properly after a week of biology [5]
will try later
anirudh.. can you please mark th epoints on your graph.. atleasst x=1 and y=1
then i will have more idea.. :)
No pink.....so i was right...wrong as usual.....can some bhaiya pls tell me where the fallacy lies and how i can correct it??
PS: Don't mind the english.....after-effect of today's english exam [3]
Same as the graph of
(y-\frac{1}{2})^{2}= 4x
for 0<x<1 and 0<y<1
VERY VERY VERY ROUGH GRAPH......TELL ME IS IT IS CORRECT AND THEN I'LL TELL U THE MEASUREMENTS [4]
(\begin{Bmatrix} y \end{Bmatrix}-\frac{1}{2})^2=4\begin{Bmatrix} x \end{Bmatrix}
if 0≤x<1
den
(\begin{Bmatrix} y \end{Bmatrix}-\frac{1}{2})^2=4 x
==>
{y} -1/2=2√x
==>
{y}=2√x + 1/2
but {y}<1
==>
2√x+1/2< 1
==>
√x<1/4
==>
x<.0625
sir, isnt this ezzy??
periodic wid integers.......
for,1>y>0;1>x>0;
(y-0.5)2 = 4x
now copy,paste this in entire first quad.......
similarly -1<y<0; & 1>x>0
(1+y-0.5)2 = 4x
again copy-paste