1
Arshad ~Died~
·Oct 4 '09 at 23:12
i mean it wont be a curve or anything....just a set of points......am i right??
1
Arshad ~Died~
·Oct 4 '09 at 23:28
its the fast and the furious site..;-)
1
Philip Calvert
·Oct 4 '09 at 23:27
my god everything here is happening at lightning fast speed ... :D
62
Lokesh Verma
·Oct 4 '09 at 23:26
@ Philip.. good one... :)
@ Arshad.. never be sorry for making mistakes... every one does it :)
1
Philip Calvert
·Oct 4 '09 at 23:26
Yes so the remaining point will be (-1,-1)
106
Asish Mahapatra
·Oct 4 '09 at 23:25
@phillip: nice one ...
@honey: so the point will be (-1,-1) which is the only point satisfying the second curve as the sum of three squares is zero implying that individual terms are zero
24
eureka123
·Oct 4 '09 at 23:24
wow philip.......
so for that expression to be zero...
x=y ,x=-1,y =-1
=> (-1,-1)
1
Arshad ~Died~
·Oct 4 '09 at 23:23
i think phillip has already written what nishant sir was asking for.........:-)
1
Philip Calvert
·Oct 4 '09 at 23:22
2[(x−y)2+(x+1)2+(y+1)2]
1
Arshad ~Died~
·Oct 4 '09 at 23:22
sorry sir...it was just a thought.....i will delete it
62
Lokesh Verma
·Oct 4 '09 at 23:20
but then x2+y2=1 is also symmetric about y=-x :P
62
Lokesh Verma
·Oct 4 '09 at 23:17
@arshad... Can you give a good justification to why it will be a set of points
@ Honey.. yes u are right.. but those will be taken care by x+y=1 .. ie by x=-1 *when y=2
1
Honey Arora
·Oct 4 '09 at 23:16
itz also valid if u put y=2
so thr wld be more pts
1
Arshad ~Died~
·Oct 4 '09 at 9:23
tooooooo much working
too complex graph.....will post it as soon as i draw it....
62
Lokesh Verma
·Oct 4 '09 at 23:09
@arshad.. what do you mean 2 points?
1
Arshad ~Died~
·Oct 4 '09 at 23:08
there will be only two points (x2 + y2 + x+ y +1-xy)=0
that at x=-1
and y=-1
62
Lokesh Verma
·Oct 4 '09 at 23:06
No honey..
okie.. let me give a hint...
this is the sum of a few squares..
62
Lokesh Verma
·Oct 4 '09 at 23:01
eureka.. there is a better way to look at that expression given :)
24
eureka123
·Oct 4 '09 at 22:58
no uttara..
here a=1,b=1,h=-1/2 =>ab-h2>0 => ellipse
62
Lokesh Verma
·Oct 4 '09 at 22:56
lol.. neither..
you havent looked at the expression closely enuf ;)
62
Lokesh Verma
·Oct 4 '09 at 22:38
You have missed something...
see arshad's post
24
eureka123
·Oct 4 '09 at 11:00
what integer soln ?????
we have to sketch whole graph...............
24
eureka123
·Oct 4 '09 at 10:49
should I unhide my ans now ????since it is confirmed it is correct ??
1
Arshad ~Died~
·Oct 4 '09 at 10:38
x3 + y3 + 3xy=1
(x+y-1)(x2 + y2 + x+ y +1-xy)=0
so eure is right about the x+y-1 line
:-)