Graph of the Day - Daily Graph 08-08-09

1

Arshad ~Died~ ·2009-10-04 23:12:38

i mean it wont be a curve or anything....just a set of points......am i right??

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Arshad ~Died~ ·2009-10-04 23:28:33

its the fast and the furious site..;-)

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Arshad ~Died~ ·2009-10-04 23:27:25

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Philip Calvert ·2009-10-04 23:27:22

my god everything here is happening at lightning fast speed ... :D

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62

Lokesh Verma ·2009-10-04 23:26:29

@ Philip.. good one... :)

@ Arshad.. never be sorry for making mistakes... every one does it :)

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1

Philip Calvert ·2009-10-04 23:26:29

Yes so the remaining point will be (-1,-1)

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Honey Arora ·2009-10-04 23:26:18

got it..:)

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24

eureka123 ·2009-10-04 23:26:16

:P

smae posts everywhere...

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106

Asish Mahapatra ·2009-10-04 23:25:08

@phillip: nice one ...

@honey: so the point will be (-1,-1) which is the only point satisfying the second curve as the sum of three squares is zero implying that individual terms are zero

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24

eureka123 ·2009-10-04 23:24:46

wow philip.......

so for that expression to be zero...
x=y ,x=-1,y =-1

=> (-1,-1)

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Arshad ~Died~ ·2009-10-04 23:23:42

i think phillip has already written what nishant sir was asking for.........:-)

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1

Philip Calvert ·2009-10-04 23:22:28

\frac{[(x-y)^2+(x+1)^2+(y+1)^2]}{2}

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Arshad ~Died~ ·2009-10-04 23:22:03

sorry sir...it was just a thought.....i will delete it

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62

Lokesh Verma ·2009-10-04 23:20:58

but then x²+y²=1 is also symmetric about y=-x :P

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62

Lokesh Verma ·2009-10-04 23:17:48

@arshad... Can you give a good justification to why it will be a set of points

@ Honey.. yes u are right.. but those will be taken care by x+y=1 .. ie by x=-1 *when y=2

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Honey Arora ·2009-10-04 23:16:15

itz also valid if u put y=2
so thr wld be more pts

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Arshad ~Died~ ·2009-10-04 09:23:00

tooooooo much working
too complex graph.....will post it as soon as i draw it....

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62

Lokesh Verma ·2009-10-04 23:09:45

@arshad.. what do you mean 2 points?

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Arshad ~Died~ ·2009-10-04 23:08:37

there will be only two points (x2 + y2 + x+ y +1-xy)=0
that at x=-1
and y=-1

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62

Lokesh Verma ·2009-10-04 23:06:57

No honey..

okie.. let me give a hint...

this is the sum of a few squares..

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62

Lokesh Verma ·2009-10-04 23:01:29

eureka.. there is a better way to look at that expression given :)

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24

eureka123 ·2009-10-04 22:58:51

no uttara..
here a=1,b=1,h=-1/2 =>ab-h²>0 => ellipse

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62

Lokesh Verma ·2009-10-04 22:56:41

lol.. neither..

you havent looked at the expression closely enuf ;)

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eureka123 ·2009-10-04 22:51:38

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62

Lokesh Verma ·2009-10-04 22:38:59

You have missed something...

see arshad's post

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24

eureka123 ·2009-10-04 11:31:22

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eureka123 ·2009-10-04 11:00:39

what integer soln ?????

we have to sketch whole graph...............

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1

$ourav @@@ -- WILL Never give ·2009-10-04 10:59:42

integer solution are x=-1 and y=-1

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eureka123 ·2009-10-04 10:49:55

should I unhide my ans now ????since it is confirmed it is correct ??

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Arshad ~Died~ ·2009-10-04 10:38:33

x³ + y³ + 3xy=1
(x+y-1)(x² + y² + x+ y +1-xy)=0
so eure is right about the x+y-1 line
:-)

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Daily Graph 08-08-09

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