62There is a small issue with the minima that you have made palani
11sir aap chate hai ki i should draw the graph to get pink[4]
62
Lokesh Verma
·2009-03-10 03:20:04
yes manipal.. to a great extent yes...
@palani.. so your graph needs some improvement :)
11
Mani Pal Singh
·2009-03-10 03:17:34
sir yeh graph kuch kuch G.O.D (10/3/09 ) JAISA HI HOGA
BAS CONCAVITY MEIN FARAK PADEGA
AND VIRAG ITS NOT DEFINED AT x=0 ALSO
BUT ISS BAAR YEH EK EVEN FUNCTION HAI
SO SAME GRAPH ON LEFT SIDE AS IT IS IN THE RHS
62
Lokesh Verma
·2009-03-10 03:12:44
what is the nature of the graph at x=-infinity and + infinty
11Therefore the reduced eq is
y = \frac{(x^2 + 1)^2}{(x^2 - 1)^2}
1i hope the graph would be like
it is not defined at x=0,1,-1
as concluded by above guys
1as the origal expressoin has aterm of '1/x'
11
Mani Pal Singh
·2009-03-10 01:51:10
YEHI TO MAIN KEH RAHA THA[2]
YAAR TU APNI MARZI SE UPPER NICHE KAAT NAHIN SAKTA
ITS AGAINST THE RULZ
U CAN FIND THE LIMITING VALUE AS TAPAN DID IT
11
virang1 Jhaveri
·2009-03-10 01:50:11
y is not defined at 0 manipal
p.s. y is not " why " here
11
virang1 Jhaveri
·2009-03-10 01:49:19
Domain = (-∞ , 1) U (1,∞)
Range = (0 , 1) U (1, ∞)
11
virang1 Jhaveri
·2009-03-10 01:37:14
Therefore it is not defined at x = 1
