Daily Graph 09-03-09

y=\frac{(x+\frac{1}{x})^2}{(x-\frac{1}{x})^2}

17 Answers

62
Lokesh Verma ·

There is a small issue with the minima that you have made palani

62
Lokesh Verma ·

yup.. :)

1
palani ............... ·

i hope it would be like this

11
Mani Pal Singh ·

sir aap chate hai ki i should draw the graph to get pink[4]

1
palani ............... ·

will add it soon

62
Lokesh Verma ·

yes manipal.. to a great extent yes...

@palani.. so your graph needs some improvement :)

11
Mani Pal Singh ·

sir yeh graph kuch kuch G.O.D (10/3/09 ) JAISA HI HOGA
BAS CONCAVITY MEIN FARAK PADEGA

AND VIRAG ITS NOT DEFINED AT x=0 ALSO
BUT ISS BAAR YEH EK EVEN FUNCTION HAI

SO SAME GRAPH ON LEFT SIDE AS IT IS IN THE RHS

1
palani ............... ·

graph would be tendin to 1

62
Lokesh Verma ·

what is the nature of the graph at x=-infinity and + infinty

11
virang1 Jhaveri ·

Therefore the reduced eq is

y = \frac{(x^2 + 1)^2}{(x^2 - 1)^2}

1
palani ............... ·

i hope the graph would be like

it is not defined at x=0,1,-1

as concluded by above guys

1
Grandmaster ·

as the origal expressoin has aterm of '1/x'

11
Mani Pal Singh ·

YEHI TO MAIN KEH RAHA THA[2]
YAAR TU APNI MARZI SE UPPER NICHE KAAT NAHIN SAKTA

ITS AGAINST THE RULZ

U CAN FIND THE LIMITING VALUE AS TAPAN DID IT

11
virang1 Jhaveri ·

y is not defined at 0 manipal
p.s. y is not " why " here

11
virang1 Jhaveri ·

Domain = (-∞ , 1) U (1,∞)
Range = (0 , 1) U (1, ∞)

21
tapanmast Vora ·

y not defined at x=0;

lim x-->0 y-->1

11
virang1 Jhaveri ·

Therefore it is not defined at x = 1

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