11sir from (0,1 ) it is obviously 1 na
and from (-1,0) we will alternate positive and huge values[1]
10 Answers
11no solution from (0,∞)
as the R.H.S is 1 from (0,1) and the L.H.L will be always from (0,1)
later on a
when x>1
then R.H.S will always be more than 1
so no positive solution
and we can check there is no solution from (-∞,0)
so no solution[1]
11It will be a blank graph since {y} that means that x[x] therefore x has to be between (-1,1) if 0<x<1 then [x] will be 0 and therefore the {y} will be 1 which is not possible and for -1<x<0 and [x] will be -1 and x is less then 0 and {y} will be negative which is not possible
62manipal i think you made a very small mistake in one line..
You should have written rhs=1
Other wise it is correct :)
1162yes it is one.. but see what you have written ;)
as the R.H.S is 0 from (0,1) and the L.H.L will be always from (0,1)
21VIRANG!!!!!!!!!1
"(-1,1)"
This is da range u hav mentioned for {y}
Dude its disastrously wrong!!!
{.} can never ever be negative..... its range is only from [0,1)