Daily Graph 10-08-09

First worry only about the interval (0,1)

will the graph be periodic in x?

To put the question differently...

if (p, q) is a point on the graph, then will (p+1, q) be a point on the graph

It will be!!

if {p} = {p+1}

isnt it!

yes so that is why i said is it periodic in x...

if it is then you dont need to worry too much about x.. but about y..

so now does that make this problem far simpler?

{x}² + {y²} = 1

{x}² = 1 - {y²}

I look only at x lying between 0 and 1

x = √1- {y²}

Which will be a circle of radius one between the square of (0,0) to (1,1)

Then there will be a flatter curve between y = [1,√2] then [√2,√3] and so on...

After doing this much repeat the graph along the x axis... .

This is after many days that i am drawing a graph myself.. (so excuse me for any mistakes :P)

no it will be symmetric about the x axis.. because f(y)= f(-y)