Daily Graph 12-02-09

IIT JEE Tutorials › Graph of the Day questions › Daily Graph 12-02-09

Plot this one.. It is interesting.
x⁴=x²y-y³

#Miscellaneous #Graph of the Day

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7 Answers

1

skygirl ·2009-02-13 07:59:42

been trying this for last 1/2-n hour ...

kuchh ni sujhraa.... :( :(

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1

mkagenius ·2009-02-13 09:08:25

equation coming is:

by putting x²=t...then solving quadratic eqn. in t.
we get....

x=Â±âˆš(yÂ±âˆš(y²-4y³)).........

what will b the graph????....

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1

skygirl ·2009-02-13 17:54:12

[12]

bhaiya ... any hint-shint dijiye .....

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1

voldy ·2009-02-13 18:05:45

this turns out as x⁴=y(x²-y²)

and also x⁴=y(x+y)(x-y) thus the asymptotes are known , w.k.t that it apsses trhu origin then unable to proceed.

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1

voldy ·2009-02-13 18:12:28

I think this's bakwaas .sry will thik properly and post later.

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62

Lokesh Verma ·2009-02-13 21:16:34

for this one that mkagenius got, we can say that y has a bound to it.

what is that bound?

Srinath you have a good point kind of .... we can know some asymptodes :)

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39

Dr.House ·2009-02-13 21:19:22

are the bounds of y [0, 1/4] ????????????

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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