Graph of the Day - Daily Graph 13-01-08

11

Subash ·2009-01-13 09:17:10

saw yesterdays problem

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11

Mani Pal Singh ·2009-03-19 04:32:40

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62

Lokesh Verma ·2009-01-13 20:51:54

yup it is all these lines

x=0, 1, âˆš2, âˆš3, âˆš4,..........

That will give the graph of this function :)

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33

Abhishek Priyam ·2009-01-13 09:23:51

I was thinking if x² is integer then it will satisfy but was not convinced that it is the only one...

Damn.... :(

x²=I.. too many vertical lines

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62

Lokesh Verma ·2009-01-13 09:23:43

did u get some hint? :)

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11

Subash ·2009-01-13 09:22:59

y=0

sry i was being stupid got it

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62

Lokesh Verma ·2009-01-13 09:21:56

equation of x axis is given by???

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11

Subash ·2009-01-13 09:20:38

but still wts the graph i dont get it i mean theres no y

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62

Lokesh Verma ·2009-01-13 09:20:28

that din help?

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62

Lokesh Verma ·2009-01-13 08:56:09

arrey isko mat bhoolo...

not that dirty question

it is a 1 liner.... very very very very similar to yesterdays....

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62

Lokesh Verma ·2009-01-13 09:16:08

how did u reach ur conclusion? (instinct based?)

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11

Subash ·2009-01-13 09:16:02

{x}={x^2+x}

so x=x^2+x+I

X^2=-I

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33

Abhishek Priyam ·2009-01-13 09:11:51

I think only difference will be for -1

then this is also absurd :P

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62

Lokesh Verma ·2009-01-13 09:11:48

no pryam...

ur thought process is not in the right direction for this one..

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33

Abhishek Priyam ·2009-01-13 09:10:36

{x}=f

f=f²

is it right.. [7]

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33

Abhishek Priyam ·2009-01-13 09:09:33

{x}={x(x+1)}

it is more visible now i think.... to me at least..

Ab age sochte hainn

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62

Lokesh Verma ·2009-01-13 09:00:26

no subash..

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11

Subash ·2009-01-13 08:58:56

would the graph of y=x^2+x be of any help

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