11simplifies to
1/2={x2}
so x2=1/2+[x2]
10 Answers
62subash.. there is a much simpler way..
why did you need the second step.
The first step ws good enough!
11See consider x as a + b where a is the integer part while b is the fractional part
(a+b)2 = a2 + b2 + 2ab
Since it is {x2} be we will consider b2 + 2ab
Therefore by substituting a = 1,2,3,....n and b by considering
2b2 + 4ab = 1
11\left\{x^2 \right\}=\frac{1}{2}
Thus
x^2=\frac{1}{2}+I ; \; where\; I\; is\; an\; Integer
So i agree with mani and palani's basic graph shapes but.....no lines will appear to the left of I=0...............this is because, after that, I will be <-1/2 and I+1/2 will be <0.......
So the lines will be
x=\pm \sqrt{0+\frac{1}{2}};\; \; \; x=\pm \sqrt{1+\frac{1}{2}};\; \; \; x=\pm \sqrt{2+\frac{1}{2}},..............
Bhaiya, pls see if i'm correct