The given equation can be written as
log 3/log x =2x-3.
log 3=(2x-3)log x log 3=log(x)2x-3
i.e. 3=x2x-3
I couldn't find any value of x satisfying this equation
Q The number of solutions of logx3=2x-3.
Better use graphical approach and try if this could be done by any another method?[1]
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10 Answers
PROCEDURE to draw the GRAPH of x^(2x-3)
possible if x>0 (ok??)
at x =1 it is one
at x = 1.5 it is one hence between x =1 and x=1.5 it takes a turn..
also at x = 0 it is infinite
and for higher values of x it approaches to infinity..right?
after x=1.5 it will always increase??clear??(no need to do dy/dx)..just try and observe its behaviour by putting values
similarly for x<1
(two solutions)
@ yes
PLZZZZZZZZZZ DONT POST COMPUTER GENERATED GRAPHS[16][16]
WE ARE TRYING HERE TO IMPROVE OUR SOLVING SKILLS ONLY.....SOO PLZZZDONT REPEAT IT[1][1]
Sorry Honey i didn't saw ur earlier posts
[1]
But 4m next time do write continued!