Daily Graph 13-07-09

The given equation can be written as
log 3/log x =2x-3.
log 3=(2x-3)log x log 3=log(x)^2x-3
i.e. 3=x^2x-3
I couldn't find any value of x satisfying this equation

PROCEDURE to draw the GRAPH of x^(2x-3)

possible if x>0 (ok??)

at x =1 it is one
at x = 1.5 it is one hence between x =1 and x=1.5 it takes a turn..

also at x = 0 it is infinite
and for higher values of x it approaches to infinity..right?

after x=1.5 it will always increase??clear??(no need to do dy/dx)..just try and observe its behaviour by putting values

similarly for x<1

(two solutions)

@ yes
PLZZZZZZZZZZ DONT POST COMPUTER GENERATED GRAPHS[16][16]
WE ARE TRYING HERE TO IMPROVE OUR SOLVING SKILLS ONLY.....SOO PLZZZDONT REPEAT IT[1][1]

plot 1/log ₃x and 2x-3

3 and x^2x-3

i hv drawn this from #2 and #4

yes honey is right

gud..that is correct graph of x^(2x-3)

Sorry Honey i didn't saw ur earlier posts
[1]
But 4m next time do write continued!