11@philip what do you think of 11 and 12
62rohit for such problems always avoid decimal notation...
always make sure to use "pi" isstead of 3.14
not that it is wrong.. but yeah.. you need to be "perfect"
62
Lokesh Verma
·2009-01-15 06:44:39
yes something like this rohit
62
Lokesh Verma
·2009-01-15 06:41:58
11 makes some sense but not complete sense
1not th full thing...its just for pii/2.........
11[11]
i never knew this thread existed!!
62
Lokesh Verma
·2009-01-14 22:14:06
[sin (x+{y})] = 1
so x+{y}=2npi+pi/2
x=2npi+pi/2-{y}
The answer is written up here.... (It is not a curved thing...) It are a lot of straight line segments!! :O
1no reply ?? no comments ??
1
skygirl
·2009-01-14 10:11:03
aur kuchh nahi tha ??
[2]
also give modulus somewhere [3]
sorry [2]
1
skygirl
·2009-01-14 11:11:50
yes philip u are correct... i missed it :P
1how npi/2
what if n is 2 or even 3
11
Subash
·2009-01-14 11:05:54
how did u get the 4th step
1
skygirl
·2009-01-14 11:03:35
sin(...) = 1
=> (...) = npi/2
=> x + {y} = npi/2
=>{y} = -x +npi/2 a
m i 1% correct ??
i am hopeless in graphs [2]
1357:)
it is ok.. it is not very easy to master graph.
How do you do it?
(Hint you have to take cases)
11
Subash
·2009-01-14 10:36:41
got my mistake thnx for correcting me
1357
Manish Shankar
·2009-01-14 10:32:50
x+y=I+npi+pi/2
is wrong..
see carefully it should be
x+y=[y]+npi+pi/2
11
Subash
·2009-01-14 10:24:28
can u tell me where is my mistake
11
Subash
·2009-01-14 10:18:02
please tell me if my method is correct
1357
Manish Shankar
·2009-01-14 10:12:08
Nishant diya tha.. :P
and he says that this is very simple!
