Daily Graph 14-07-09

we get x²-2 = 2[x]
So, x must be an integer.
So, [x] = x
SO,
x²-2x-2=0
==> x=(2±√4+8)/2 which does not give any integral values of x.

SO, NO SOLUTION

edits:
one solution. only
the mistake i had made was that x² must be an integer. This does not imply that x must be an integer. x can be be √k where k is a whole no.
From gordo's graph (perfect),
we see that x lies in (2,3) so [x]=2
So, x² = 2 + 2[x] = 2+4 = 6
So, x = √6 is the only solution of this equation.

1 soln. dat way..

x²-2-2[x]=0
x²-2=2[x]
x²-2/2=[x]
This is graph of x²-2/2 and [x]
Hence it has one solution
*edited

HONEY UR ANSWER IS WRONG .
gODO PLS GIVE THE ANSWER ACC TO U [1]

#2 nd #3 are differnt.............which one is correct
n wtz wrong in my ans?

honey recheck ur answer
u will find mistake

:O

****we get x2-2 = 2[x]
So, x must be an integer.********

how u can say that ashish??

see if x is some square root of a integer ,even then ..............
correct me if i am wrong

edited in #5.............tell me if i m wrong even nw.....