Daily Graph 15-07-09

4^x-2[x]=y

[x]=0 for x belongs [0,1)

we have to do the same for all the other intervals.

its basically this
for x = [k,k+1)
the equation is y=4^x/4^k here u shud take x as [0,1)

i m not sure bt the grph on right side wud be sumwat lyk

@vector: there will be concavities and convexities please show them.
the values u have shown are fyn.
Also show the portion of negative x.

vector u did it wrong
asish perfect work[1]