Daily Graph 15-07-09

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Q
Draw the graph of 4^{x}-[x]

#Miscellaneous #Graph of the Day

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8 Answers

11

Mani Pal Singh ·2009-07-15 21:58:44

any takers?

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62

Lokesh Verma ·2009-07-15 22:08:25

wow mani.. your graphs are rocking these days..

no takers?!

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3

msp ·2009-07-15 22:12:58

4^x-2[x]=y

[x]=0 for x belongs [0,1)

we have to do the same for all the other intervals.

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106

Asish Mahapatra ·2009-07-15 22:15:36

its basically this
for x = [k,k+1)
the equation is y=4^x/4^k here u shud take x as [0,1)

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1

vector ·2009-07-15 22:21:42

i m not sure bt the grph on right side wud be sumwat lyk

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106

Asish Mahapatra ·2009-07-15 22:24:10

@vector: there will be concavities and convexities please show them.
the values u have shown are fyn.
Also show the portion of negative x.

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106

Asish Mahapatra ·2009-07-15 22:30:41

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11

Mani Pal Singh ·2009-07-17 22:17:55

vector u did it wrong
asish perfect work[1]

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω