Graph of the Day - Daily Graph 15-8-09

1

abhishek upadhyay ·2009-10-17 00:29:23

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Lokesh Verma ·2009-10-17 00:33:55

no abhishek

look at the point 0+i

z² = -1

|z² - 4| = 5

Whihch is far far bigger than 1

Even the origin does not satisfy the property

[1]

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62

Lokesh Verma ·2009-10-19 23:51:06

This one is still unsolved !

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iitimcomin ·2009-10-22 23:33:48

|z-2||z+2|=1 ...........

((x-2)^2 + y^2)((x+2)^2 + y^2) < 1

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RAY ·2009-10-22 23:54:43

it will be a fourth degree curve as far as i m gettin by solving it

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iitimcomin ·2009-10-22 23:59:31

its obvious frm ... #6 its fourth degree ..

and its symmetric abt x and y axis ............

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iitimcomin ·2009-10-23 00:23:57

and the curve intersexts the x axis at x = -root(3) and root(3) .....

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iitimcomin ·2009-10-23 00:29:17

approx the above area???

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Lokesh Verma ·2009-10-23 04:14:41

Yes IITimcoin.. this is very good work :)

You have almost found the answer.. though the shape is slightly different...

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iitimcomin ·2009-10-23 20:25:45

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arpan sinha ·2009-11-02 03:19:28

HINT:

\left|z ^{2}-4\right|\leq 1
or z \in [\sqrt3,\sqrt5]
thus there is reflection on y axis.
do u want more hints to be given?
tougher one...

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