3|z-2||z+2|=1 ...........
((x-2)^2 + y^2)((x+2)^2 + y^2) < 1
|z2-4|<1
Where z is any complex number on the Argand plane..
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11 Answers
62no abhishek
look at the point 0+i
z2 = -1
|z2 - 4| = 5
Whihch is far far bigger than 1
Even the origin does not satisfy the property
[1]
3its obvious frm ... #6 its fourth degree ..
and its symmetric abt x and y axis ............
3and the curve intersexts the x axis at x = -root(3) and root(3) .....
62Yes IITimcoin.. this is very good work :)
You have almost found the answer.. though the shape is slightly different...
1HINT:
\left|z ^{2}-4\right|\leq 1
or z \in [\sqrt3,\sqrt5]
thus there is reflection on y axis.
do u want more hints to be given?
tougher one...