Daily Graph 16-04-09

draw the graph of

y=x sin{x}

12 Answers

1
palani ............... ·

|xsin{x}|<=|x|

so graph lies b/w y=x&y=-x

is ma approach right?

62
Lokesh Verma ·

yes palani

the approach is perfectly correct :)

11
Mani Pal Singh ·

the graph of the function will be many one

24
eureka123 ·

@ rip ,wont it be concave up???

24
eureka123 ·

and why max value remains same???

62
Lokesh Verma ·

yes rip.. see carefully there is a mistake.. infact 2 major ones..

11
Mani Pal Singh ·

sorry sir i did y =sin{x} earlier
Now for y=x sin{x}
we have to check it like from (0,1) it would be x sin x and from (-1,0) it would be x sin x+1
So it graph mite be
Analyzing x sin x =y
so
y'=sin x + x cos x >0 (0,1)
y"=cos x + cos x - x sin x >0 from (0,1)

and

y= x sin (x +1)
y'=sin(x+1) + x cos(x+1)
y"=cos (x+1)+cos(x+1) - sin(x+1) >0 (-1,)
so its graph could be like shown

3
msp ·

mani in the graph all the values of y shud be positive since x and sin{x} are all positive

3
msp ·

y=xsin(x-[x])

y'=sin(x-[x])+xcos(x-[x]) >0 for all x >0 and is <0 for all x<0

we have continuity at x=0 so we will have a minima at zero.

And the graph has discontinuity at all other integer pts bcos {x}=0

i think with these we can draw the reqd graph.

11
Mani Pal Singh ·

bhai msp
when we take x -ve then x will be negative and sin{x} will be positive
check it out

3
msp ·

no mani {x} is negative for all nos less than zero.

11
Mani Pal Singh ·

[11][11][11][11][11][11]
can {x} be negative at any value
[11][11][11][11][11][11]

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