Daily Graph 17-06-11

reviving..! [1]

Draw the graph of [xy]=1

[.] denotes greatest integer function.

22 Answers

1
aditya ravichandran ·

sorry i am redrawing , but ashish it will be in 2nd quadrant

11
epsilon ·

hyperbola symmetric about the origin

1
rishabh ·

could someone help me with this,
let S ≡ f(x,y) , |||x|-2|-1|| + |||y|-2|-1| = 1.
If S is made out of a wire then the length of the wire required is?
this came in our fiitjee aits test 1 today. ( i don't think it is possible to solve this within 4 minutes)

1
satyajit maurya ·

thank you rishabh

1
rishabh ·

@satyajit,
notice that due to the |x| , |y| the graph will be symmetrical in all the 4 quadrants.
and another point to note is that 1 - [|x|] cannot be negative since box of a positive number (|y| ) has to be positive.
so the geaph is bounded between x = -2 and +2 and same for y.

now take cases;
case1: 0≤ x < 1
[x] = 0

case2: 1≤x<2
[x] = 1.

using this draw the graph in first quadrant and replicate to other quad.

btw, nishant sir and all other bhaiyas why dont you continue this thread by posting questions like graph of the week
this will also save your time and be a good revesion tool for us.

1
satyajit maurya ·

nishant sir,can you please explain asish's solution of the second graph?

62
Lokesh Verma ·

why should u be hurt if you are correct...

these are not allegations... just that i want to make sure that u guys dont stop learning....

yeah ur graph is perfect and ur method too is

[1]

1
aditya ravichandran ·

@nishant sir ,

this is not true

i drew the graphs of y=1/x
y=1.1/x
y=1.2/x
.
.
.

y=2/x

using software

for the advantage of the students here to understand it clearly
and super imposed these graphs

and fyi ,no graph making software can make graphs of [x] and {x}

i thought you could have understood it

leaving all these behind ...
lets us focus back on some intellectual stuff

can we calculate the area ???

although i was deeply hurt by your allegations

62
Lokesh Verma ·

Yup but unfortuately like many others u too used a graphing software instead of trying it on your own :(

1
aditya ravichandran ·

bhaiya is this oen right ??

62
Lokesh Verma ·

no dude.. not the 2nd quadrant...

1
Ricky ·

1 ≤ x y < 2

So , a number of hyperbolas , what else ?

62
Lokesh Verma ·

Ashish... Good to see ur progress... I wish the others also become active....

30
Ashish Kothari ·

Won't there be more curves in the third quadrant as well?

1
aditya ravichandran ·

to the original question

30
Ashish Kothari ·

What a feeling to have got a pink in this legendary section of GODs! [3]

30
Ashish Kothari ·

Is ricky bhaiya's graph like this :

From, y=2 onwards, there will no value of x which will satisfy the given equation.. so the graph.. [1]

1
Ricky ·

Another graph -

[ | y | ] = 1 - [ | x | ]

49
Subhomoy Bakshi ·

All the best Ricky! Even my IIT counselling results come on 21st! [4]

1
Ricky ·

It's on 21 - st , I am going to Bangalore the day after tomorrow .

49
Subhomoy Bakshi ·

hehe!

Yeah Ricky: what abt the interviews??

62
Lokesh Verma ·

We have to start banning this guy called Ricky :D

So that he doesnt take away everyone's thunder :D

@Ricky ... how was ISI?

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