Daily Graph 17-07-09

Q
Draw the graph of [x]/{x} from [-3,3]

13 Answers

11
virang1 Jhaveri ·

For The graph between (0,1) There will be no graph 0/x =0
For (1,2)
[x] = 1 which is a constant
let u = {x}
y = 1/u
yu = 1
This the graph of the rectangular hyperbola with lowest value 1
For (2,3)
y = 2/u
yu =2
it is also a hyperbola with lowest value = 2
For (-1,0)
y = -1/u
yu = -1
it is also a hyperbola with highest value = -1
For (-2,-1)
y = -1/u
yu = -2
it is also a hyperbola with highest value = -2
For (-3,-2)
y = -1/u
yu = -3
it is also a hyperbola with highest value = -3

11
virang1 Jhaveri ·

is my graph rite sir

The hyperbola in the solution mean a part of it

11
Mani Pal Singh ·

na ji na
study the definition of {x} again and den try the question!

1
°ღ•๓яυΠ·

rite side is right ..left mein gadbad hai :)

take

-1.2

so [x]=-2 ....n {x}=.8............

n so on

11
Mani Pal Singh ·

please draw[1]

24
eureka123 ·

looks like everyone forgot abt this one.....
just completing it...

the red lines indicate graph..the black ones are just grids

62
Lokesh Verma ·

no eureka..

you have done a fantastic job.. but you seem to have missed something on the left side..

what is it?

62
Lokesh Verma ·

Virang;s graph was very good.. he just overlooked a small thing as pointed out by mrunal..

1
$ourav @@@ -- WILL Never give ·

wont d graph be in 1st and 3rd quadrant??

62
Lokesh Verma ·

yes ...

it will be :)

24
eureka123 ·

yeah it will be in 3rd quad and not in 2nd..but nay other mistake ?

62
Lokesh Verma ·

yup i think so.. :)

1
$ourav @@@ -- WILL Never give ·

eureka,den make corrections and post d graph again

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