MERA LOGIC
SEE IT WONT BE DEFINED AT 0 AND PI/2
ISKI VALUE PI/3 AND PI/6 PE SAME HAI
ISKI ASYMPTOTE HAI X=0 AND X=PI/2
SO IT WAS AN INTUTIONISTIC LOGIC (MERE KO PATA NAHIN KI YEH KYA HOTA HAI PAR KUCH HOTA HAI)[3]
MERA LOGIC
SEE IT WONT BE DEFINED AT 0 AND PI/2
ISKI VALUE PI/3 AND PI/6 PE SAME HAI
ISKI ASYMPTOTE HAI X=0 AND X=PI/2
SO IT WAS AN INTUTIONISTIC LOGIC (MERE KO PATA NAHIN KI YEH KYA HOTA HAI PAR KUCH HOTA HAI)[3]
the game here is on f'(x)
dy/dx = sec2x(tanx - 1)/2(tanx)3/2
now as its only defined 4 +ve values of tanx
dy/dx < 0 for tanx < 1 .......... x<45................ decreasing func
dy/dx > 0 for tanx > 1 .......... x>45................ inc functn
and assymptotes will be lines x = n(pi/2)
Anuj ke graf jaisa hi kuch.......
iski 0 pe value kitni hogi bhai???
aur yaar ek baat dekh iski value pi/3 and pi/6 pe value same hogi
aur when x tends to 0 yeh ∞ hoga and same when x tends to pi/2
sahi kahan
pi/3, pi/6 pe values will be same
so by symmetry you are again right...
at zero it will tend to +infinity
also
minima will be at pi/4!
why?
sir iski value
pi/4=√2
pi/3=pi/6=√1/√3+√√3>2
thanx sir
now i got my mistake
thanx 4 bringing out the right concept and realizing of my mistake