1hmm... can anyone confirm the answer??
27 Answers
9these are sure curves and not straight lines an elegant approach wud be to divide whole plane into squares of unit dimensions with vertices as integers and then cutting arcs of radius √1.5 choosing centres as lowerleft vertice for each square . the intercept of that circle within the concerned sqr gives graph
1http://targetiit.com/iit_jee_forum/posts/daily_graph_05_03_09_3042.html
62anirudh if there was some post where i did that..
please tell me..
I may have made a mistake
but essentially what ith power did is correct :)
11but some graphs in tiit of similar functions have been posted by tapan in the manner i have posted the first graph......and bhaiya said that was right
i'll give u the links wait
11according to nishant sir in #10
your image needs a bit more clarity.. In the sense that you have not put circles in the right places..
and your diagram seems to be wrong in the 2nd, 3rd and 4th quadrants..
what does he mean by the bolded statement
1the graph will be uniform over all quadrants
because if you put x as x+1 you get the same further put y as y+1 then also you get the same ..
so work backwards and you get that the graph is uniform over all quadrants
11hey, guys...what abt my graph?? I've drawn all 4 quadrants
11wat about the other quadrants
ROHAN
please draw this in in 2nd ,3rd,4th quadrants also!!!!!!!!!!
3y2+x2-2(y[y]+x[x])-1.5=0
when [y]=0 and [x]=0
it will be a circle with center at origin and of radius √1.5
when [x]=0 and [y]=1
a circle having center (0,1) and radius √2.5
when [y]=0 and [x]=0
a circle have center (1,0) and radius √2.5
62your image needs a bit more clarity.. In the sense that you have not put circles in the right places..
and your diagram seems to be wrong in the 2nd, 3rd and 4th quadrants..
1yes sir
that is definite
because there will be only some values as x=√0.75 and y=√0.75
62quite good this time..
but there is a bit more ..
will the different small arcs be of the same size?
1it is really a beutifula dn conceptual question
but Mr RIP made a mess out of it
i suggest him not to try questions which r beyond his scope[16]
Nishant sir please verify my answer
62but the point you have plotted on the curve has
the point (√3/2, 0)
Now does that satisfy the original equation?
11sir when x and y r 4m (0,1)
then we have
x2+y2=3
the fraction part vanishes
so i can't get ur point