Daily Graph 18-5-09

f(0)- = 0 ? [11][11]

it seems correct to me,aur maine rough diagram banaya hai, to the scale nahi :)

just check first & second derivative

haan bhai just check the limits

f(0^-)=lim(h→0⁺)-he^(-1/h)=0

lim x-> 0⁺ f(x)= ∞
lim x-> 0^- f(x)=0

we have f'(x)= e^1/x - e^1/x/x
= e^1/x(1-1/x)

so f(x) is increasing in (1,∞)
decreasing in (0,1)

for x belongs ro R^-
we have limx->-∞ f(x) =-∞

the graph is -∞ at -∞, increases to 0 at 0, is discontinuous at 0, decreases to obtain a minima at x=1, or f(x)=e, and then increases to infinity as x→∞

inshort its gonna be the same as above.. :):):)
cheers!!