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4 Answers
1it seems correct to me,aur maine rough diagram banaya hai, to the scale nahi :)
just check first & second derivative
haan bhai just check the limits
f(0-)=lim(h→0+)-he(-1/h)=0
1lim x-> 0+ f(x)= ∞
lim x-> 0- f(x)=0
we have f'(x)= e1/x - e1/x/x
= e1/x(1-1/x)
so f(x) is increasing in (1,∞)
decreasing in (0,1)
for x belongs ro R-
we have limx->-∞ f(x) =-∞
the graph is -∞ at -∞, increases to 0 at 0, is discontinuous at 0, decreases to obtain a minima at x=1, or f(x)=e, and then increases to infinity as x→∞
inshort its gonna be the same as above.. :):):)
cheers!!