Graph of the Day - Daily Graph 19-02-09

39

Dr.House ·2009-02-21 00:14:15

if this is the case, it is sin(x+y)=a

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106

Asish Mahapatra ·2009-02-21 23:50:08

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21

tapanmast Vora ·2009-02-21 06:36:13

SLOPE OF THE GRAF : -1 thruout......

intercepts change..........

as

2nÎ + sin^-1a
or
(2n+1)Î - sin^-1a

provided -1<=a>=1

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11

Mani Pal Singh ·2009-02-21 06:35:05

sir for my prospect a SHOULD be mentioned

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62

Lokesh Verma ·2009-02-21 06:30:46

btw the graph was wrong :)

ashish posted this scrap to me to tell me :)

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1

skygirl ·2009-02-21 00:54:48

wow!! this graph thread is looking so beautiful !! all pink pink...

btw ... nice questions :)

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62

Lokesh Verma ·2009-02-21 00:29:36

good work ashish..

:)

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21

tapanmast Vora ·2009-02-21 00:16:53

wat timing!!!

1:35
1:36
1:36

LOL

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106

Asish Mahapatra ·2009-02-21 00:15:19

x+y = 2nÎ + sin^-1a
or
(2n+1)Î - sin^-1a

So, it will be infinite no. of straight lines of two types:
TYPE 1:
slope = -1
parallel to line of y-intercept = sin^-1a at regular y-intercepts of 2Î

TYPE 2:
slope = -1
parallel to line of y-intercept = Î -sin^-1a at regular y-intercepts of 2Î

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39

Dr.House ·2009-02-21 00:02:39

this is sinxcosx=1

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39

Dr.House ·2009-02-21 00:12:41

cubes bhool gaye kya? or this is the question??????????

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62

Lokesh Verma ·2009-02-21 00:11:35

because this one is a sitter for a graph of the day question.. lets do some more varaitions.

sinx. cosy + cosx siny = a

draw the graph

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106

Asish Mahapatra ·2009-02-21 00:09:14

if it is 2,
then sin2x= 4 again does not exist.

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106

Asish Mahapatra ·2009-02-21 00:08:39

general.....
sinxcosx=a
==>sin2x = 2a
So, -1/2â‰¤aâ‰¤1/2 then only it is possible.
Then x = nÎ /2 + (-1)ⁿsin^-1a/2

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21

tapanmast Vora ·2009-02-21 00:06:21

[11] [11] [11] [11] [11] [11] [11] [11] [11] [11] [11] [11] [11] [11]

that means 2sinxcosx = 2;

sin(2x) = 2;

thats not possible

null graf???????

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62

Lokesh Verma ·2009-02-21 00:06:02

How about

sin³x cosx + cos³x sinx =2

and

sin³x cosx + cos³x sinx =a

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106

Asish Mahapatra ·2009-02-21 00:05:27

there is no solution according to me...
Bhaiyya what am i getting??
sinxcosx=1
==>2sinxcosx=2
==>sin2x=2 which is impossible so no solution...
kya yeh sahi hai?

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