Daily Graph 21-02-09

for x>1 y=2{x}²

y=2(x)² + 1 - 2x + I;

thus parabola

y = (√2x - 1/√2)² +0.5

vertex = (0.5,0.5)

no sorry again!! :( [2]

its wrong got ma mist.......

i'm out of form today it seems

HOPE THIS UN IS RITE :
ALL THESE SHAPES ARE PARABOLAS, NOT SEMI-CIRCLES (LOL)

(y-0.5) = (√2x - 1/√2)²

DISCONTINUITY AT x=integers as y=0 ther....

at integer points {x} is 0 so y =0
and not 1
check ur graph again tapan

oh so discontinuity at x ε Integers....

at integer points... y=0;

otherwise the framework remains da same huh...

I hav made a lot ofblunders in this un :( [2]

i agree with u sir

not so much so coz i m not personally satisfied onthis un as

"IN LIFE THER ARE NO 2nd CHANCES!!!" [1]