21for x>1 y=2{x}2
14 Answers
21y=2(x)2 + 1 - 2x + I;
thus parabola
y = (√2x - 1/√2)2 +0.5
vertex = (0.5,0.5)
21no sorry again!! :( [2]
its wrong got ma mist.......
i'm out of form today it seems
21HOPE THIS UN IS RITE :
ALL THESE SHAPES ARE PARABOLAS, NOT SEMI-CIRCLES (LOL)
(y-0.5) = (√2x - 1/√2)2
DISCONTINUITY AT x=integers as y=0 ther....
11at integer points {x} is 0 so y =0
and not 1
check ur graph again tapan
21oh so discontinuity at x ε Integers....
at integer points... y=0;
otherwise the framework remains da same huh...
I hav made a lot ofblunders in this un :( [2]
21not so much so coz i m not personally satisfied onthis un as
"IN LIFE THER ARE NO 2nd CHANCES!!!" [1]