Daily Graph 21-08-09

NO one?

I guess the new users need to start particiating..

I have heard this from a lot of users that we visit the site but not post there.. I dont think passive particiation is of much use... generally your thought process should improve and unless you all show what's in your mind it is difficult to improve..

y not?

f(x)=x²-x³ = x²(x-1)

thus f(1)=f(0)=0

again

f'(x)=0 when 2x-3x²=0

i.e. at x=0 and x=2/3

at x=2/3 the function reaches local maxima and at x=0 it reaches local minima

thus the graph will be characteristic (negative)cubic graph with x axis tangent at x=0 and with a crest at x=2/3 wen f(2/3)=4/27(if calculation isnt wrng)

cuts x axis at x=1 and goes down till minus infinity for x>1

and again for x<0 goes up till infinity...

no the graph will be like this!