(x+y-x+y)/(x-y) = 0
=> y/(x-y)=0
=> y=0
i.e. the graph is x-axis excluding the origin
x+yx-y=1
This might seem very stupid. but still i think this is slightly relevant...
Btw I am starting back the Graph of the day section... I was short of very good basic graphs after having posted over 100 graphs... The other graphs would generally be out of syllabus and we would go into stuff which is not useful for jee..
Hopefully some of you will learn from these :)
(x+y-x+y)/(x-y) = 0
=> y/(x-y)=0
=> y=0
i.e. the graph is x-axis excluding the origin
Good you din fall for the origin trap...
This was a warming up graph.. bcos we havent dealt with graphs for a few months now..
except manipal who keeps posting some of these :)
why excluding the origin ?(is it because (0,0) makes the expression undefined?)
only on x-axis,origin have same same ordinates n abcissa.......