Graph of the Day - Daily Graph 27-01-09

1

big looser ......... ·2009-01-28 05:11:04

who is pinki

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1

pankaj sachan ·2009-01-29 10:11:46

graph should exist only for +ve x axis and it should be concave downward. mkagenius plotted the correct graph.

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62

Lokesh Verma ·2009-01-28 20:45:17

you are absolutely right abhishek... (see the posts..)

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33

Abhishek Priyam ·2009-01-28 20:23:39

but it thought √ is positive sq root and ()^1/2 the Â±

But is it the opposite..

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62

Lokesh Verma ·2009-01-28 10:57:18

@everyone...

Well... I din want to get into all this discussion.... bcos it wud confuse everyone...

Now that this has come we should realise that

√x and x^1/2 are not the same!!

When we talk of one, it means + and - while the ohter means only the +ve root...

What abhishek is saying is essentially correct... But I did not want to get into this question of definitions :)

Please remember that a lot of it has to do with definitions......

I still dont think I am unpinking that first pink.... (cos Here i was not trying to catch u guys on the -ve thing)

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24

eureka123 ·2009-01-28 09:13:52

@virang..............use some calculus dear.............this point plotting wont take u far..............(sorry if u feel i am harsh,but its truth)

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11

virang1 Jhaveri ·2009-01-28 07:58:52

³√x=√y+1
therefore
(y+1)³= x²
x² = y³ + 1 +3y(y+1)

Therefore
when
y = 0, x =Â± 1
y = 1, x =Â±2√2
y = 2 ,x =Â±√27
y = -1 x = 0
y = -2 x=√-1

Therefore values of negative y cannot be plotted on the graph

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24

eureka123 ·2009-01-28 07:18:03

There may be some flaws...........forgive me.......

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33

Abhishek Priyam ·2009-01-28 05:25:08

i designed it myself... ;)

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1

mkagenius ·2009-01-28 05:24:10

read above posts, u will get two correct graphs....identify it....

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33

Abhishek Priyam ·2009-01-28 05:23:05

which i posted ;) not the pink one...

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1

big looser ......... ·2009-01-28 05:21:34

then wats the right ans bro

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33

Abhishek Priyam ·2009-01-28 05:16:27

lol

pink post is pinkie...

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1

mkagenius ·2009-01-28 05:15:55

ok....
didnt see ur post

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1

mkagenius ·2009-01-28 05:15:15

ya u r rite,,,,
but graph should only exist in x>0

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1

moon ·2009-01-27 09:15:19

this eq cn be written as x²=(y+1)³
i think the reqd. graph is.......

bt i m nt sure.............:)

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33

Abhishek Priyam ·2009-01-28 05:05:55

wrong pinki... :P

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33

Abhishek Priyam ·2009-01-28 05:05:06

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