yes sir, the circles are where the graph wont exist i.e. x=1,3,5.... i.e. all odd integers
8 Answers
Asish Mahapatra
·2009-09-29 00:58:40
Lokesh Verma
·2009-09-29 01:00:17
what about x = 1.01 ??
and if i said that the graph will exist there
take x=1, y=1
Asish Mahapatra
·2009-09-29 01:06:29
lolz. yes... my mistake ... not thinking too much it will be the quarter circles repeated in each quadrant
they should be semicircles not lookng lyk semicircles at all
again mistake{x} means the graph of +ve side should be repeated in the negative side....
so correct graph is