Daily Graph 27-07-09

BITSAT 2015 Sample Questions › Graph of the Day questions › Daily Graph 27-07-09

{x}²+y²=1

#Miscellaneous #Graph of the Day

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8 Answers

106

Asish Mahapatra ·2009-09-29 00:53:01

taking x in (0,1) the equation is x²+y²=1

lyl < 1

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62

Lokesh Verma ·2009-09-29 00:56:08

no asish.. this is not correct..

think again :)

what about x=-1?

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106

Asish Mahapatra ·2009-09-29 00:58:40

yes sir, the circles are where the graph wont exist i.e. x=1,3,5.... i.e. all odd integers

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62

Lokesh Verma ·2009-09-29 01:00:17

what about x = 1.01 ??

and if i said that the graph will exist there

take x=1, y=1

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106

Asish Mahapatra ·2009-09-29 01:06:29

lolz. yes... my mistake ... not thinking too much it will be the quarter circles repeated in each quadrant

they should be semicircles not lookng lyk semicircles at all

again mistake{x} means the graph of +ve side should be repeated in the negative side....

so correct graph is

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62

Lokesh Verma ·2009-09-29 01:10:15

still not done :D :P

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xYz ·2009-09-29 01:16:26

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62

Lokesh Verma ·2009-09-29 02:22:56

NOw both of you are right :)

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