1where is y !
if i m talking foolish then forget it:D
16 Answers
62Hmm... good question.. but not good enuf to deserve an answer yet ;)
33let [x]≠{x}
then by multiplying both sides by {x}-[x]
we get...
x=5({x}-[x])
x=5{x}-5[x]
x=5{x}-5(x-{x})
x=10{x}-5x
6x=10{x}
{x}=3x/5
solving it we get x=0
but x≠0 as {x}-[x]≠0
so none :)
?33:) i think this should be the answer....... unless i made some calculation mistake...........
15{x} = 3x --------(1)
=> 8{x} = 3[x]
x=3/4, [x]=2 satisfying...
but again its not satisfying (1).
!! ??
62Yeah this was easy wasnt it :)
now try this one... a slight variation...
{x}+[x] = 5
[x]-{x}
62{x}+[x] = 5
[x]-{x}
{x}+[x] = 5[x]-5{x}
6{x} = 4[x]
{x} = 2/3[x]
{x} =0, 2/3 .. these are the only 2 options...
[x] = 0 or 1 correspondingly..
x cant be zero...
hence only one solution x=5/3