Graph of the Day - Daily Graph 28-01-09

3

msp ·2009-02-04 10:18:03

y=e^x-[x]-1

for [x]=1 y=e^{-2+ x}

for [x]=2 y=e^x-3

for [x]=-1 y=e^x

for every integer values the graph has a change in x by x+1 or x-1

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106

Asish Mahapatra ·2009-02-04 10:19:40

All curves are parallel
the points are 1/e

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Lokesh Verma ·2009-02-04 10:21:31

ashish can you tell what are the values at those points?

and will the slope of the curve be concave or convex?

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Asish Mahapatra ·2009-02-04 10:22:29

for slope dy/dx>0 and d²y/dx²>0

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Dr.House ·2009-02-04 10:23:25

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Dr.House ·2009-02-04 10:24:33

this is the graph of y=e^{x}.

the blue lines r not a part o the graph.

i dont know how to do y=e^{x}-1

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Lokesh Verma ·2009-02-04 10:24:49

good work ashish.. :)

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Dr.House ·2009-02-04 10:24:56

from this graph i gave can we get the required graph?

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Lokesh Verma ·2009-02-04 10:26:00

@ b555...

You repeated the part above between 0 and 1

you needed to do repeat between parts -1 and 0

that wud be this graph :)

cheers :)

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