{x} =1/2 alone
4 Answers
Asish Mahapatra
·2009-05-06 20:42:41
x-[x]-2x+[2x]=1/2
==> x=[2x]-[x]-1/2
==> {x} = 1/2 as LHS = integer - 1/2 = integer +1/2
x-[x]-2x+[2x]=1/2
==> x=[2x]-[x]-1/2
==> {x} = 1/2 as LHS = integer - 1/2 = integer +1/2