Daily Graph 31-12-08

VITEEE 2015 Preparation › Graph of the Day questions › Daily Graph 31-12-08

e^x = 2^-{y}

#Miscellaneous #Graph of the Day

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30 Answers

62

Lokesh Verma ·2009-01-08 20:37:36

@sky no this is not the graph...

@varun.. This not a function! (so i think we should not use the word range!)

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9

Celestine preetham ·2009-01-09 01:02:13

coolehsrtol ur graph is correct if u replace -.027 by - .693 also there will be points on y axis cos x = 0 means y is integer which is very much possible

i donno wat aragorn trys to say

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62

Lokesh Verma ·2009-01-09 00:49:12

that was not needed.. i mean rohit made a smalll mistake in plotting those points..

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62

Lokesh Verma ·2009-01-09 00:48:42

it is essentially the same aragorn..

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11

Anirudh Narayanan ·2009-01-09 00:42:27

you mean they tend towards -0.693 but never reach there? Btw why have you marked there as -0.27?

I plotted my graph according to reply #11 [1]

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1

RAY ·2009-01-09 00:37:19

hey the arrows start from the y axis............the arrow heads show..they wont exactly reach sumwhere..where i cannot exactly tell...........

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11

Anirudh Narayanan ·2009-01-09 00:34:41

What are the arrow heads for? [7]

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1

RAY ·2009-01-09 00:30:23

no probs........

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1

RAY ·2009-01-09 00:29:46

dis is the perfect one...........

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11

Anirudh Narayanan ·2009-01-09 00:27:57

Sorry, Rohit[2]. I was blabering in my sleep[13][13][13][13][13]

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62

Lokesh Verma ·2009-01-09 00:27:20

no rohit ur graph is not correct! :(

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1

RAY ·2009-01-09 00:24:58

guys i guess mah was correct

simple explanations...

wen x=0.....e^x=1 and so at all integral points on y axis where x=0....{y}=0........so (1/2)⁰=1...............hence it is valid at all integral points on y axis...........

now takin log on both sides.....we get x= - 0.3 .{y}..........where y =Integer part + fractioanal part.....so {y}=f

so we get x=-0.3 .f

where f is between 0 and 1....so the velue of 0.3*f <1 always....

so we get that when f=0.1.....x = - .03 and wen f=.9.....x=.27

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1

RAY ·2009-01-09 00:22:14

guys i guess mah was correct

simple explanations...

wen x=0.....e^x=1 and so at all integral points on y axis where x=0....{y}=0........so (1/2)⁰=1...............hence it is valid at all integral points on y axis...........

now takin log on both sides.....we get x= - 0.3 .{y}..........where y =Integer part + fractioanal part.....so {y}=f

so we get x=-0.3 .f

where f is between 0 and 1....so the velue of 0.3*f <1 always....

so we get that when f=0.1.....x = - .03 and wen f=.9.....x=.27

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11

Anirudh Narayanan ·2009-01-08 23:50:03

There won't be any points on the y axis as on yaxis x=0 and e^nonsenseâ‰ 0. I don't think the graph which I posted and deleted is correct. But I'll put it anyway.[4]

POINTS ON THE Y AXIS ARE NOT INCLUDED

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1

varun ·2009-01-08 21:59:02

co-domain ?

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1

skygirl ·2009-01-08 11:11:35

this is very tuf..

seems at first look...

feelin toooooooooooo sleeeeeeeeeepppppppppyyyyyyyyyyy

zzzzzzzzzzzzzzzzzzzzzzzzzz

:(

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1

varun ·2009-01-08 20:30:27

Range is all real numbers

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1

skygirl ·2009-01-08 20:15:42

HIGHLY DOUBTFUL ...

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1

skygirl ·2009-01-08 20:11:27

e^x = 2^-{y}

range= [1/2⁰ , 1/2)

so e^x Îµ [1,1/2)

e^x=1 => x=0

e^x=1/2 =>x=ln(1/2) = -0.693

so domain=(-o.693,0]...

is it??

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1

varun ·2009-01-08 12:09:40

lol rectangle ? i am not able to draw graph properly with paint :S

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62

Lokesh Verma ·2009-01-08 12:01:42

yup this seems to make more sense :)

so what's the graph like?

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1

varun ·2009-01-08 11:56:10

taking log both sides -

x = -{y} ln 2.
x=-0.693{y}

hmm.. yes a portion where -0.693<xâ‰¤0 and y Îµ R

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62

Lokesh Verma ·2009-01-08 11:50:35

i think that for every y, we can find a unique value of x!!

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1

varun ·2009-01-08 11:48:20

but the equation is true only for x = 0 right ?

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62

Lokesh Verma ·2009-01-08 11:43:48

infact for every y, there will be a value of x.. isnt it?

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62

Lokesh Verma ·2009-01-08 11:41:49

there will be many more i think!

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1

varun ·2009-01-08 11:37:54

sorry :D, x = 0 and y = any integer. y-axis.

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62

Lokesh Verma ·2009-01-08 11:33:53

varun look carefully.. if there is one point there will be infinite..

{y} is fractional part

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1

varun ·2009-01-08 11:31:41

I think it is only a point lol

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62

Lokesh Verma ·2009-01-08 11:14:17

even i dont know the answer yet :D

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω