4No Sanchit My B'day is on 31st Feb (never saw my profile ??) And both r not the answers to the riddle though
I am not posting the ans
Let us w8 for any other idle brain
\int_{-1}^{2}{x^2} dx
whats the need to integrate ?????jsut fill in values..
(2)^2-(-1)^2
=4-1
=3
[3][3]
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23 Answers
4
1@johndover..... math will b fun if u try to do something like this...maybe u will end up with a great formula or a principle that could fetch u the ABEL prize!!!!!
1consider
a=b
*a on both sides
a2=ab
subtract b2 on both sides..
a2-b2=ab-b2
( a+b)(a-b)=b(a-b)
(a+b)=b
sustituting b in the place of a (a=b)
b+b=b
2b=b
2=1
lolzzzzzzzzzzzzzzzzzzzzzzzzz
11your birthday is on 31 december
The day before yesterday (December 30) you were 25.
you turned 26 on December 31.
you talked about it on January 1. That year you would become 27, so "next year" you would be 28.
1lol. the answer to this is moving the 2 of 102 up, to make it 102
anyways, iitjee results not coming in time has surely made u guyz a bunch of idle lot. :D
cheers!!
24@ #11
101 - 102 = 1
interchange '-' and '=' signs to get 101=102-1 [1]
24another one...this has even more blunders.... [3]
\int \frac{1}{x+1} dx
\int \frac{1}{x}+ \frac{1}{1}dx=\int\frac{1}{x}dx +\int\frac{1}{1}dx =logx+log1=log(1+x)
4What mathematical symbol can be placed between 5 and 9, to get a number greater than 5 and smaller than 9?
4The day before yesterday I was 25 and the next year I will be 28. This is true only one day in a year. What day is my birthday?
4Rectify the following equality 101 - 102 = 1 by moving just one digit.
u can move the diigits anyway though [3]
1haha no. im idle too,...but not a guy, im afraid :P :P
24every complex no. is real [3][3]
z=re^{i \theta}
when θ≠0,let α=eiθ
\alpha ^{2 \pi /\theta}=(e^{i \theta})^{2 \pi /\theta}=e^{i 2\pi}=1
=>\alpha= 1^{\theta /2\pi}=1
hence proved [3]
24\sum_{1}^{\infty}{\frac{1}{(k+1)(k+2)}}
whats hte ans ???
can it have two ans ???
looks noo...but there are...
1)put k =1,2...
1/6 +1/12 + 1/20 +... =(1/2 -1/3)+(1/3 -1/4)+(1/4-1/5)+....=1/2
2)again same thing but diff way
1/6 +1/12 + 1/20 +...=(1-5/6)+(5/6-3/4)+(3/4-7/10)+...=1 [3][3]