See this!

The exponential function ex is strolling along the road insulting the functions he sees walking by. He scoffs at a wandering polynomial for the shortness of its Taylor series. He snickers at a passing smooth function of compact support and its glaring lack of a convergent power series about many of its points. He positively laughs as he passes |x| for being non differentiable at the origin. He smiles, thinking to himself, "Damn, it's great to be ex. I'm real analytic everywhere. I'm my own derivative. I blow up faster than anybody and shrink faster too. All the other functions suck."

Lost in his own egomania, he collides with the constant function 3, who is running in terror in the opposite direction.

"What's wrong with you? Why don't you look where you're going?" demands ex. He then sees the fear in 3's eyes and says "You look terrified!"

"I am!" says the panicky 3. "There's a differential operator just around the corner. If he differentiates me, I'll be reduced to nothing! I've got to get away!" With that, 3 continues to dash off.

"Stupid constant," thinks ex. "I've got nothing to fear from a differential operator. He can keep differentiating me as long as he wants, and I'll still be there."

So he scouts off to find the operator and gloat in his smooth glory. He rounds the corner and defiantly introduces himself to the operator. "Hi. I'm ex."

"Hi. I'm d /dy."

15 Answers

1
aieeee ·

ha,ha,ha...good fun, dude!

1
Akand ·

i dint understand d last sentence....................so wat if he is d/dy???

i thought ex will learn a lesson sum how.....

1
yes no ·

d/dy(ex) = 0 :)

1
JOHNCENA IS BACK ·

wat was ultimate joke in last line???????????????i din get................[3]

1
Sanjit Vignesh ·

Wish lessons were taught with humor like this.

1
Anjalee ·

It was a gud one!!!

11
SANDIPAN CHAKRABORTY ·

fanatstic.... [1][1][1][1][1][1][1][1][1][1][1][1][1][1]

11
Aditya Balasubramanyam ·

Superb..... But is x also Variable ?? then he needmt be worried

1
pranav ·

awsome!

1
Shankar C ·

how d/dy. (ex) = 0 pls explain.

39
Pritish Chakraborty ·

When differentiating wrt y, x is a constant term, thats why. You'll learn this in partial differentiation.

1
ntvirus within ·

there's a suicide bomber, who can kill ex.
guess who...??
yeah... (-ex)
;-D

39
Pritish Chakraborty ·

lol..only if it is added...if its multiplied, not so :P

1
Shankar C ·

d/dy (ex) = ex.dx/dy na?

1
Arka Halder ·

ya shankar,you're right.
it had to be specified that y and x are independent of each other.

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