i see that nobody posted a solution. let me give you the answer:
the reaction equilibrium shifts in forward direction!!
can you explain why?
please give a detailed reasoning to your solution::
[CoCl4(H2O)2]2- + (edta)4- = [Co(edta)]2- + 4Cl- +2 H2O ALL ARE aquous.
if H2o is added in above equilibrium(initially it is in equilibrium) what will happen?
i see that nobody posted a solution. let me give you the answer:
the reaction equilibrium shifts in forward direction!!
can you explain why?
how come ? u're increains the [product] , so reacn should proceed in the backward direcn no ?
Ok. so let me tell you the reason, as soon as you give water, which is excess it makes a solvation isomer replacing one cl by an H2O. this is because, H2O is a strong field ligand than Cl; but Edta is stronger, and the product Co(Edta)2- is a very stable compound due to chelation. so again edta replaces H2O and gives you the product.
i am getting some very high funda explanations here but for me reasoning is very easy
first-: concentration of H2O will not change
second-:adding water will reduce the concentration of all the species
third-:value of Qc wil becomes less than Kc
final-: rxn will move in forward direction