29
govind
·2010-03-15 03:05:27
Ans 2 ..first statement is true..
looks like u did some typo in the second statement..i am unable to make out the difference between Thalium Tri-iodide and Thallium Tri-iodide except that 'l' ....no prob...in Thallium Tri-iodide Thallium is in +1 oxidation state and Iodine exits as I3- ...so it is isomorphous with CsI3 and NH4I3..
now the third statement is true..
HNO2 + 2H2SO4 → NO2+ + H3O+ + 2HSO4-... so van't Hoff factor is 4...actually i = ≈3.82 in this case
the fourth statement is false...wanna now how..u can see NCERT alkyl halides chapter..
11
Devil
·2010-03-16 01:06:45
Yes. The typo is that there will be ammonium-tri-iodode in place of the 2nd thalium tri-iodide.
Govind give the nas finally to the 2nd qsn. Mind u we've to get the wrong statements.
1st one is str8 from NCERT. 2nd one is from MTG.
29
govind
·2010-03-16 01:18:44
For the second question..only statement D is false...rest are true...
29
govind
·2010-03-16 11:36:56
About Ur First question i dont think that it's straight from NCERT....
I think that the answer shud be C and D as Al and Zn have amphoteric oxides and can form soluble salts with excess NaOH....
That's wat i think..maybe it's right..
1
aieeee
·2010-03-18 01:19:55
1) 2NaOH + H2O2 → Na2O2 + 2 H2O
Na2O2 + Cr(OH)3 → Na2CrO4 + H2O.
Actually , as H2O2 is available , its sure to be involved in some redox reactions. so, its surely not c and d. and a relevant reaction is not possible for a).
3
iitimcomin
·2010-03-19 06:30:07
so wat conclution in Q1>>