29Q.2 D (Electron Affinity is indirectly calculated from Born-Haber's Cycle)
Q.3 B
Q.4 B
@Ashish can u plz explain 5 and 8..
Single Option Correct.
1) Electron Affinity is +ve when-
A) O- is formed from O.
B) O 2- is formed from O-.
C) O+ is formed from O.
D) Electron Affinity is always negative.
2)Of the 4 ∂H values needed to calculate the lattice Energy using Born-Haber's Cycle, the most difficult one to measure is-
A) Heat of sublimation of the metal.
B) Heat of formation of gaseous atoms of non-metal.
C) Ionisation Energy of the metal.
D) Electron Affinity of the non-metal.
3)Which of the foll. forms a stable +4 oxidation state-?
A) Lanthanum B) Cerium
C) Europium D) Gadolinium
4)Select incorrect order of size of atoms/ions-
A) I+ < I < I-
B) Fe=Co=Ni
C)Ni<Cu<Zn
D) None is Incorrect.
5) In which case Effective Nuclear Charge is minimum -?
A) Be B) Be2+
C) Be3+ D) Equal.
6)With respect to Oxygen, maximum valency is shown by-
A) Halogen family
B) Oxygen family.
C) NItrogen family.
D) Boron Family.
7) Elements X & Y have valence shell electronic Config. as-
X: ns2np5 Y: ns2np3
Which compound is likely to be formed among them-?
A) X3Y5 B) Y3X5
C) XY D) YX
8) For Be, Zeff =1.95 & for Bex+ , Zeff =2.30. "x" is -
A) 1 B) 2 C) 3 D) 0
9)Ionic Hydrides react with water to give-
A) Basic sol.n
B) ACidic sol.n
C) A hydride ion.
D) Protons.
10) Out of BeH2, CuH2, CrH3, & NaH, covalent hydrides are-
A) BeH2,NaH B) CuH2,CrH3
C) BeH2,CuH2,CrH3 D) All of these.
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15 Answers
106Q1. (B) the already present charge repels the even extra negative charge. :P
Q2. (D) ? (not sure)
Q4. AC are correct. Not sure abt B
Q5. (A)
6. (a)
Q7. im getting none
Q8. a
Q9. a
Q10. I would say only BeH2
29
131) Rite (B). But since it wud gain a noble gas config., i thot engy wud be released.
2) D correct. Kaise ?
4) Ans is D.
5) & 8) Rite asish, but i haven't got a clue of wat all this is about...needing an elaborate explanation.
6) A is rite. Wht does the Qn mean actually ?
7) Ans is D.
9) U're rite.
10) C.
106Q4. yeah just looked up the values Fe 1.17
Co 1.16
Ni 1.15
So approx equal
2. explained by govind...
EA cannot be calculated directly
5. All u have to rem is that effective nuclear charge means that mro is its value smaller is the atom (that is what i know)
6. Iska matlab ki O ke saath kaun sabse jyaada variation in oxidation states de sakta hai
8. Tukka (THere is some calculation involved which im not sure)
10. JD Lee says that
BeH2 is intermediate between ionic and covalent
CuH2 is intermediate between covalnet and interstitial
CrH3 is interstitial
106lagaa. ki as the nuclear charge increases not too much (only 0.35) it is reasonable to assume that only 1 electron has been ionised..
btw this is also not in JEE
6cud u please tell me wat exactly is there in jee n wat nt...means d topics??if u have ny link thn please giv....y to study thngs whn they r'nt required.......:)
13k theek hai, thnx [1]
Waise, is born-haber's a part of thermodynamics?...'coz i haven't done tht yet.
So, only 7) & 10) left to be resolved.
6arrey hain yarr...m so stup....thnks yarr..........:D
47) D is √
Becz on pairing with Y , X attains stability {full filled} & Y anyway is half filled
13Uttara, plz elaborate....means Y will be cation, X anion....or else ther'll be no difference b/w options C & D.