MECHANICS QUE!!!

Who takes the trouble of typing more letters
when not needed....
by the way u r right.

i think : we should never take the equality sign in friction questions ...

that will lead to a confusion whether anything that we are getting is maximum or minimum..

here its told 'maximum' so ok....

but this is not always the case...

i have added the last equation Tapan;
solving those gives max dis. A=0.2m.

as already solved by the girl from sky....:)

same method i must hav made a stupid calculation mistake

of course it is 0.2 .

all might have got the FBD ..

horizontal : Tcosθ = f ------1

vertical : Tsinθ + N = Mg -------2

f ≤ μN => Tcosθ ≤ (Mg - Tsinθ)

=> T ≤ μMg/ (cosθ + μsinθ) --------3

Tcosθ = kx -------- 4

from 3 and 4 ,

x ≤ (...u can get it... :P )

bus [1]

is the ans 0.25m

SEE ABOVE

theta=x
Tsinx+N=Mg;
Tcosx=uN;
kA=Tcosx;

AM I CORRECT??

u told dog moved 0.25m
then max. force the spring can provide is 400*0.25=100N
THEN how could tension b more than 100N

subhash ,,,,
can u tell what will b the value of tension in the string ??
and d direction of friction?

why is this in inorganic section