i quite understood...thank you...:)
i saw dis question in j.d.lee...there isn't any answer given...
it says-a transition element usually exhibits higher oxidation state in its fluorides than it does in its iodides.
a detailed explanation will b of great help.:)
p.s.- has it got something to do with the electronegativity of fluorides n iodides?
-
UP 0 DOWN 0 0 6
6 Answers
no...
It has to do with electron gain enthalpy..!
Try to think a bit! [1]
electron gain enthalpy is higher in case of fluorides...
so lower will b d tendency of fluorines to accept electrons...
but how does dat account for d tendency of transition elements to show higher oxidation states in case of flourides???:-(
Higher electron gain enthalpy means more energy will be released when one electron is accepted by fluorine than by iodine...
now think..[1]
higher electron gain enthalpy means on accepting one electron more energy will be released by the atom..
on release of more energy, the system becomes more stable..
and every substance in chemistry drools for stability..
fluorine gains more stability on accepting electron than iodine and thus the tendency to accept electron will be more in fluorine than in iodine..
Thus ur comment abt tendency to accept electrons was a "bit" wrong!