a) a=41nm
b) d=35.5nm
Q: CsCl has BCC structure in which Cs atoms occupy Body Center and Cl the corner sites. If density is 3.99 g/cc , Calculate :
a) The length of edge of Unit Cell
b) The distance b/w Cs+ and Cl- ions
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4 Answers
Aditya Bhutra
·2012-02-22 08:38:27
use d= z*MNA*a3
putting z=1 , M = 168.5 , Na =6*10^23 , d=3.99 g/cc
a= 4.12 angstrom
now body diagonal = a√3
distance between the ions = a√32 = 3.57 angstrom
@swaraj - i think you made a mistake in units of 'a'
Vivek @ Born this Way
·2012-02-23 00:47:20
Then I;m correct.. I also got the same i.e, 412 pm.. But the material said 519 pm .. Huh.. Thanks all.