Solid State

JEE Advanced 2015 Papers › Inorganic Chemistry questions › Solid State

Q: CsCl has BCC structure in which Cs atoms occupy Body Center and Cl the corner sites. If density is 3.99 g/cc , Calculate :
a) The length of edge of Unit Cell
b) The distance b/w Cs⁺ and Cl^- ions

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#Chemistry #Inorganic Chemistry

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Swaraj Dalmia ·2012-02-22 07:37:36

a) a=41nm
b) d=35.5nm

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johncenaiit ·2012-02-22 07:47:54

is that correct by taking Z=1 ?

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Aditya Bhutra ·2012-02-22 08:38:27

use d= z*MN_A*a³

putting z=1 , M = 168.5 , Na =6*10^23 , d=3.99 g/cc

a= 4.12 angstrom

now body diagonal = aâˆš3

distance between the ions = aâˆš32 = 3.57 angstrom

@swaraj - i think you made a mistake in units of 'a'

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Vivek @ Born this Way ·2012-02-23 00:47:20

Then I;m correct.. I also got the same i.e, 412 pm.. But the material said 519 pm .. Huh.. Thanks all.

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Solid State

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