the substance formed is ?

when SnCl₂ is added to HgCl₂ , then a white precipitate of Hg₂Cl₂ is formed.

SnCl₂ + HgCl₂ → Hg₂Cl₂ + SnCl₄.

if further SnCl₂ is added, then a grey precipitate of Hg metal is obtained along with SnCl₄.

these are the analysis confirmatory tests for Sn and Hg

well can u explain y this rxn exist,but i have seen this in my buk,can u explain.

actually , when SnCl₂ is added to HgCl₂ , then Hg being at its highest oxidation state acts as oxidising agent and oxidises SnCl₂ to SnCl₄ and itself reduces to Hg₂Cl₂ i.e. the +1 oxidation state.

now,if this reaction of SnCl₂ continues wid Hg₂Cl₂ , then Hg₂Cl₂ now gets reduced by SnCl₂ to form metallic Hg and SnCl₄ is also formed.

tx.